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#25934 - 10/27/03 11:03 AM Programming Challenge: I answers
paradox Offline
Member

Registered: 08/28/03
Posts: 240
Loc: New Zealand
Ok well seeing as how this is programming i cant really write code in every langauge but instead i will use psedu which every language can incorporate

ok the challenge simply asks you to find y on the 1000th iteration where y=x*x*x-x+y
or y=x**3-x+y in other cases

well how do we do this first we need to have a loop to make it go through 1000 times
for x=1;x<1000;x++
this loop just makes it go from 1 to 1000
in the loop we just do answer=x**3-x+y
y=answer;
i do it like this to avoid any mishaps that might happen due to different languages
then at then end of loop
u just print the value.. simple huh..
so end result
initilaze values
c++ example
Code:
#include <iostream>
int main(){
int answer=0,x=0,y=0;
for(x=1;x<1000;x++){
answer=x*x*x-(y+x);
y=answer;
}
printf("%d\n",y);
//or cout << y;
return 0;
}
Hope this helped you in some way
programming is a big part of anything to do with the computer especially hacking
_________________________
The wise make mistakes, the fools repeat them
----------------------------------------
When you have eliminated the impossible, that which remains, however improbable, must be the truth

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#25935 - 10/27/03 12:13 PM Re: Programming Challenge: I answers
Ntd Offline
Member

Registered: 01/21/03
Posts: 217
Loc: Melbourne, Victoria, Australia
Why don't you move this too the C++ section.

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#25936 - 10/27/03 01:52 PM Re: Programming Challenge: I answers
paradox Offline
Member

Registered: 08/28/03
Posts: 240
Loc: New Zealand
because its a challenge answer not a programming sollution or idea.. and seeing as how my challenges are off topic so are the answers leave it up to mods :p
_________________________
The wise make mistakes, the fools repeat them
----------------------------------------
When you have eliminated the impossible, that which remains, however improbable, must be the truth

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