Posted by: Ghost

## Math problems are fun! - 07/14/06 03:04 AM

Anyone who solves the following for X, and PMs me the work and final solution (exact answer, no need to evaluate) gets a prize. I'll post the answer in a few days. If you're stuck, i'll post hints. Post the solution before I call it, and you incur my wrath!

Code:

2^X + 2^(X + 1) = 4^X + 4^(X + 1)