You all suck.

The answer is:
Code:
2^X + 2^(X+1) = 4^X + 4(X+1) //Original problem
2^X(1 + 2) = 4^X(1 + 4) //Time to factor!
2^x(3) = 4^X(5) //Simplify
(2^X) = 3/5 //Simplify and divide
log(3/5) = xlog2 //log it!
x = log(3/5)/(log(2))
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